opencv双三次插值方法
import cv2
import numpy as np
import math
def S(x):
x = np.abs(x)
if 0 <= x < 1:
return 1 - 2 * x * x + x * x * x
if 1 <= x < 2:
return 4 - 8 * x + 5 * x * x - x * x * x
else:
return 0
def function(img,m,n):
height,width,channels =img.shape
emptyImage=np.zeros((m,n,channels),np.uint8)
sh=m/height
sw=n/width
for i in range(m):
for j in range(n):
x = i/sh
y = j/sw
p=(i+0.0)/sh-x
q=(j+0.0)/sw-y
x=int(x)-2
y=int(y)-2
A = np.array([
[S(1 + p), S(p), S(1 - p), S(2 - p)]
])
if x>=m-3:
m-1
if y>=n-3:
n-1
if x>=1 and x<=(m-3) and y>=1 and y<=(n-3):
B = np.array([
[img[x-1, y-1], img[x-1, y],
img[x-1, y+1],
img[x-1, y+1]],
[img[x, y-1], img[x, y],
img[x, y+1], img[x, y+2]],
[img[x+1, y-1], img[x+1, y],
img[x+1, y+1], img[x+1, y+2]],
[img[x+2, y-1], img[x+2, y],
img[x+2, y+1], img[x+2, y+1]],
])
C = np.array([
[S(1 + q)],
[S(q)],
[S(1 - q)],
[S(2 - q)]
])
blue = np.dot(np.dot(A, B[:, :, 0]), C)[0, 0]
green = np.dot(np.dot(A, B[:, :, 1]), C)[0, 0]
red = np.dot(np.dot(A, B[:, :, 2]), C)[0, 0]
# ajust the value to be in [0,255]
def adjust(value):
if value > 255:
value = 255
elif value < 0:
value = 0
return value
blue = adjust(blue)
green = adjust(green)
red = adjust(red)
emptyImage[i, j] = np.array([blue, green, red], dtype=np.uint8)
return emptyImage
img=cv2.imread("e:\\lena.bmp")
zoom=function(img,1024,1024)
cv2.imshow("cubic",zoom)
cv2.imshow("image",img)
cv2.waitKey(0)
Comments 1 条评论
博主 opteroncx
其实opencv里的resize方法里也带了双三次插值,速度很快,建议直接使用